At the start of this season, Lie to Me took several successful chances with high-stakes, action-packed episodes like "Honey" and "Secret Santa." Now, the second half of Season 2 is surprising us again by bringing the excitement without all the explosions—most of the "action" in Monday's episode, "The Whole Truth," took place in the courtroom.
All four members of the Lightman group focused their talents on a single case, in which a young widow had been accused of murdering her older husband to gain access to his fortune. Lightman (Tim Roth) took on the case in the name of "justice," but it was obvious he just wanted to spar with his ex-wife, Zoe Landau (Jennifer Beals), who was representing the widow. As the evidence surfaced, Lightman softened and took her side to help her keep her innocent client out of jail. Landau had a unique effect on Lightman; he was more rebellious than ever in this episode, shooting his mouth off on the stand and interrogating Landau's client behind her back. But what seemed like cockiness was actually Lightman's elusive weak side, which has been making more appearances than usual in this second half of the season. He broke his own rule by staying involved in the case even though he had a very strong personal connection to it—and almost went to jail because of it. Obviously, the Lightman-Landau saga is far from over, seeing as they arrived at (and left) dinner together. Here's hoping she exposes more of Lightman's fascinating flaws before the two of them work it out—and that Lightman won't hurt his daughter Emily (Hayley McFarland) or his partner Foster (Kelli Williams) in the process.
Meanwhile, on the sidekick front, the URST between Torres (Monica Raymund) and Loker (Brendan Hines) stayed unresolved. The pair did reach a new level in their friendship, or relationship, or whatever is going on between them; much to Loker's delight/surprise/confusion, Torres revealed that she had once been with a woman. Is it ironic that his reaction was hard to read?
What did you think of "The Whole Truth"?
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